6[2-(2x-5)]=2(-3-3x)

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Solution for 6[2-(2x-5)]=2(-3-3x) equation:


Simplifying
6[2 + -1(2x + -5)] = 2(-3 + -3x)

Reorder the terms:
6[2 + -1(-5 + 2x)] = 2(-3 + -3x)
6[2 + (-5 * -1 + 2x * -1)] = 2(-3 + -3x)
6[2 + (5 + -2x)] = 2(-3 + -3x)

Combine like terms: 2 + 5 = 7
6[7 + -2x] = 2(-3 + -3x)
[7 * 6 + -2x * 6] = 2(-3 + -3x)
[42 + -12x] = 2(-3 + -3x)
42 + -12x = (-3 * 2 + -3x * 2)
42 + -12x = (-6 + -6x)

Solving
42 + -12x = -6 + -6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6x' to each side of the equation.
42 + -12x + 6x = -6 + -6x + 6x

Combine like terms: -12x + 6x = -6x
42 + -6x = -6 + -6x + 6x

Combine like terms: -6x + 6x = 0
42 + -6x = -6 + 0
42 + -6x = -6

Add '-42' to each side of the equation.
42 + -42 + -6x = -6 + -42

Combine like terms: 42 + -42 = 0
0 + -6x = -6 + -42
-6x = -6 + -42

Combine like terms: -6 + -42 = -48
-6x = -48

Divide each side by '-6'.
x = 8

Simplifying
x = 8

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